conversion of diamond to graphite is exothermic or endothermic

Likewise, although diamond is the only thermodynamically stable form of solid carbon at 200,000 atmospheres of pressure, the rate of conversion is slow below about 3000º K. Yes it is very slow in a natural setting. Describe the Aeolian Erosion, transportation and deposition processes in arid climate with an example of a sand dune formation & migration.. At 1 atm and $25^{\circ} \mathrm{C}$ , diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. At one atmosphere of pressure, graphite is the only thermodynamically stable form of solid carbon. Still have questions? Heating a diamond to 4000º Kelvin at one atmosphere of pressure (of an inert gas, like argon) will convert it into graphite more or less instantly. Don't worry about where the numbers come from. What is the free energy change for the conversion of diamonds into graphite? Click 'Join' if it's correct. Evidence from students’ data? Problem: Both graphite and diamond burn.C(s, diamond) + O2(g) CO2(g)For the conversion of graphite to diamond:C(s, graphite) → C(s, diamond) ΔH° 298 = 1.90 kJWhich produces more heat, the combustion of graphite or the combustion of diamond? Why do coal miners keep hoping the mines will reopen? It requires a negative change in enthalpy (ie an exothermic reaction) and/or a positive change in the entropy. It is often possible to calculate DH for a reaction from listed DH values of other reactions (i.e. Heating a diamond to 4000º Kelvin at one atmosphere of pressure (of an inert gas, like argon) will convert it into graphite more or less instantly. Go to your Tickets dashboard to see if you won! Add your answer and earn points. Consider the options:-A) Combustion is always an exothermic process. You must be logged in to bookmark a video. In anyone's lifetime.. or perhaps even the lifetime of planet Earth. reliable date possible? Why do coal miners keep hoping the mines will reopen? Join Yahoo Answers and get 100 points today. If carbon‑14 has a half-life of 5730 years, what is the age of the plant fossil in years? Why is the standard heat of formation of $\mathrm{CO}(g)$ difficult to measure experimentally? This is the difference between thermodynamics and kinetics. The conversion of graphite into diamond is an endothermic reaction C(graphite) --> C(diamond) Enthalpy change is +3kJ/mol Which statements are correct? View Winning Ticket, Given the following thermochemical data: $$\begin{array}{ll}\frac{1}{2} \mathrm{N}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \frac{1}{2} \mathrm{NO}(g) & \Delta H_{\mathrm{rxn}}^{\circ}=+90.3 \mathrm{kJ} \\ \mathrm{NO}(g)+\frac{1}{2} \mathrm{Cl}_{2}(g) \rightarrow \mathrm{NOCl}(g) & \Delta H_{\mathrm{rxn}}^{\circ}=-38.6 \mathrm{kJ} \end{array}$$ what is the value of $\Delta H_{\mathrm{rxn}}^{\circ}$ for the decomposition of NOCl? What is the free energy change for the conversion of diamonds into graphite? $$2 \mathrm{NOCl}(g) \rightarrow \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)+\mathrm{Cl}_{2}(g) \quad \Delta H_{\mathrm{rxn}}^{\circ}=?$$, Synthetic natural gas (SNG), sometimes called substitute natural gas, is a methane-containing mixture produced from the gasification of coal or oil shale directly at the site of the mine or oil field. Answer to Use the following data to determine whether the conversion of diamond to graphite is exothermic or endothermic. Use those data and that for the following reaction$$\begin{array}{r}\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g}) \longrightarrow \mathrm{COCl}_{2}(\mathrm{g}) \\\Delta_{\mathrm{r}} H^{\circ}=-108 \mathrm{kJ} \mathrm{mol}^{-1}\end{array}$$to calculate the standard molar enthalpy of formation of $\mathrm{COCl}_{2}(\mathrm{g})$. The conversion of diamonds to graphite is spontaneous but VERY VERY SLOW. The Study-to-Win Winning Ticket number has been announced! Don't worry about where the numbers come from. The Gibbs free energy equation, ΔG=ΔH - TΔS , is used to calculate the free energy change for a reaction or process. A diamond can change to graphite under atmospheric pressure, but the change takes place so slowly that it cannot be detected. A claim that answers the question  There is also the issue of kinetic stability. Click to sign up. \mathrm{C}(\mathrm{s}, \text { diamond })+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})} & {\Delta H=-396 \mathrm{kJ}}\end{array}$$, Calculate the standard enthalpy of formation for diamond, given that$$\begin{array}{ll}\text { C(graphite) }+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) & \Delta H^{\circ}=-393.5 \mathrm{kJ} / \mathrm{mol} \\\text { C(diamond) }+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) & \Delta H^{\circ}=-395.4 \mathrm{kJ} / \mathrm{mol}\end{array}$$, Use data from Table $10.3,$ but without performing detailed calculations, determine whether each of the following reactions is exothermic or endothermic. Hess's Law. Are the standard heats of formation of oxygen and ozone the same? - 12476361 Aishanik is waiting for your help. This time we are only requiring a subscription fee of $12 per month and you get access to professional answers available. Graphite is more stable than diamonds. Indeed, as the following phase diagram shows, diamond is the most stable allotrope of solid carbon at high pressures. Notice that Hess's Law is a little bit like the multi-step equations that we can writee when studying reaction rates. And it turns out that if we just some these chemical reactions up, we will get this overall reaction of interest.

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